If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2+60x-188=0
a = 1; b = 60; c = -188;
Δ = b2-4ac
Δ = 602-4·1·(-188)
Δ = 4352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4352}=\sqrt{256*17}=\sqrt{256}*\sqrt{17}=16\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-16\sqrt{17}}{2*1}=\frac{-60-16\sqrt{17}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+16\sqrt{17}}{2*1}=\frac{-60+16\sqrt{17}}{2} $
| 7-j=7j-5 | | 1/3(12-4a)=1/3(3-9a) | | 4(x-1)-3(x-2)+2(x-1)=10 | | 2(4+b)=9+6 | | 2x+29=21 | | m+2/3=1/4-1 | | x(6x-9)=(6x+9)(x-2) | | 3=18-5x | | -2xx=4 | | X/2+x/5+x/3=21 | | 6x^2+6x-12=60 | | X+5=13+x+2 | | -2(y-1/7)=-3y | | ((4^(x^2))(2^3x))=4 | | -6+10h=10h+4 | | 2(y-4)+7=3 | | 20+5m=3m | | 8x-71+5x-12=0 | | 3n+19=5n+17 | | 4(x+2)=5(x-8) | | x^2-5x6=0 | | 20+m=8m | | -7.3h=2.7h | | 300-2x=204 | | (22.5)=7/x | | -4r+-8=8-4r | | 60+0.70x=40=0.80x | | 4(x+2)=5(x+5) | | (-2y+5)=-3y | | 3x+34+2x+21=0 | | 16x+3=6x-7 | | X+19=8+2x+25 |